if(count >= maxSize()) count = 0;
result.first = letters[count++];
int entries = (rand() % 5) + 2;
for(int i = 0; i < entries; i++) {
int choice = rand() % maxSize();
char cbuf[2] = { 0 };
cbuf[0] = letters[choice];
result.second.push_back(cbuf);
}
return result;
}
};
int ThesaurusGen::count = 0;
const string ThesaurusGen::letters("ABCDEFGHIJKL"
"MNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz");
// Ask for a "word" to look up:
string menu(Thesaurus& thesaurus) {
while(true) {
cout << "Select a \"word\", 0 to quit: ";
for(TIter it = thesaurus.begin();
it != thesaurus.end(); it++)
cout << (*it).first << ' ';
cout << endl;
string reply;
cin >> reply;
if(reply.at(0) == '0') exit(0); // Quit
if(thesaurus.find(reply) == thesaurus.end())
continue; // Not in list, try again
return reply;
}
}
int main() {
Thesaurus thesaurus;
// Fill with 10 entries:
generate_n(
inserter(thesaurus, thesaurus.begin()),
10, ThesaurusGen());
// Print everything:
copy(thesaurus.begin(), thesaurus.end(),
ostream_iterator
// Create a list of the keys:
string keys[10];
int i = 0;
for(TIter it = thesaurus.begin();
it != thesaurus.end(); it++)
keys[i++] = (*it).first;
for(int count = 0; count < 10; count++) {
// Enter from the console:
// string reply = menu(thesaurus);
// Generate randomly
string reply = keys[rand() % 10];
vector
copy(v.begin(), v.end(),
ostream_iterator
cout << endl;
}
} ///:~
A Thesaurus maps a string (the word) to a vector
In main( ), a Thesaurus is created, filled with 10 entries and printed using the copy( ) algorithm. The menu( ) function asks the user to choose a "word" to look up by typing the letter of that word. The find( ) member function discovers whether the entry exists in the map. (Remember, you don’t want to use operator[ ], which will automatically make a new entry if it doesn’t find a match!) If so, operator[ ] fetches out the vector
In the previous code, the selection of the reply string is generated randomly, to allow automated testing.
Because templates make the expression of powerful concepts easy, you can take this concept much further, creating a map of vectors containing maps, and so on. For that matter, you can combine any of the STL containers this way.
Cleaning up containers of pointers
In Stlshape.cpp, the pointers did not clean themselves up automatically. It would be convenient to be able to do this easily, rather than writing out the code each time. Here is a function template that will clean up the pointers in any sequence container; note that it is placed in the book’s root directory for easy access:
//: :purge.h
// Delete pointers in an STL sequence container
#ifndef PURGE_H
#define PURGE_H
#include
template
typename Seq::iterator i;
for(i = c.begin(); i != c.end(); ++i) {
delete *i;
*i = 0;
}
}
// Iterator version:
template
void purge(InpIt begin, InpIt end) {
while(begin != end) {
delete *begin;
*begin = 0;
begin++;
}
}
#endif // PURGE_H ///:~
In the first version of purge( ), note that typename is absolutely necessary; indeed this is exactly the case that the keyword was added for: Seq is a template argument, and iterator is something that is nested within that template. So what does Seq::iterator refer to? The typename keyword specifies that it refers to a type, and not something else.
Although the container version of purge( ) must work with an STL-style container, the iterator version of purge( ) will work with any range, including an array.
Here is Stlshape.cpp, modified to use the purge( ) function:
//: C07:Stlshape2.cpp
// Stlshape.cpp with the purge() function
#include
#include
#include "../purge.h"
using namespace std;
class Shape {
public:
virtual void draw() = 0;
virtual ~Shape() {};
};
class Circle : public Shape {
public:
void draw() { cout << "Circle::draw\n"; }
~Circle() { cout << "~Circle\n"; }
};
class Triangle : public Shape {
public:
void draw() { cout << "Triangle::draw\n"; }
~Triangle() { cout << "~Triangle\n"; }
};
class Square : public Shape {
public:
void draw() { cout << "Square::draw\n"; }
~Square() { cout << "~Square\n"; }
};
typedef std::vector