Each public function in a class essentially forms a contract with the user; if you pass it certain arguments, it will perform certain operations and/or return a result. The same contract must hold true in derived classes; otherwise the expected "is-a" relationship between derived and base classes is violated. Since exception specifications are logically part of a function’s declaration, they too must remain consistent across an inheritance hierarchy. For example, if a member function in a base class says it will only throw an exception of type A, an override of that function in a derived class must not add any other exception types to the specification list, because that would result in unexpected exceptions for the user, breaking any programs that adhere to the base class interface. You can, however, specify
// C01:Covariance.cpp
// Compile Only!
//{-msc}
#include
using namespace std;
class Base {
public:
class BaseException {};
class DerivedException : public BaseException {};
virtual void f() throw (DerivedException) {
throw DerivedException();
}
virtual void g() throw (BaseException) {
throw BaseException();
}
};
class Derived : public Base {
public:
void f() throw (BaseException) {
throw BaseException();
}
virtual void g() throw (DerivedException) {
throw DerivedException();
}
};
A compiler should flag the override of Derived::f( ) with an error (or at least a warning) since it changes its exception specification in a way that violates the specification of Base::f( ). The specification for Derived::g( ) is acceptable because DerivedException "is-a" BaseException (not the other way around). You can think of Base/Derived and BaseException/DerivedException as parallel class hierarchies; when you are in Derived, you can replace references to BaseException in exception specifications and return values with DerivedException. This behavior is called
When
If you peruse the function declarations throughout the Standard C++ library, you’ll find that not a single exception specification occurs anywhere! Although this might seem strange, there is a good reason for this seeming incongruity: the library consists mainly of templates, and you never know what a generic might do. For example, suppose you are developing a generic stack template and attempt to affix an exception specification to your pop function, like this:
T pop() throw(logic_error);
Since the only error you anticipate is a stack underflow, you might think it’s safe to specify a logic_error or some other appropriate exception type. But since you don’t know much about the type T, what if its copy constructor could possibly throw an exception (it’s not unreasonable, after all)? Then unexpected( ) would be called, and your program would terminate. The point is that you shouldn’t make guarantees that you can’t stand behind. If you don’t know what exceptions might occur, don’t use exception specifications. That’s why template classes, which constitute 90 percent of the Standard C++ library, do not use exception specifications—they specify the exceptions they know about in
Exception safety
In Chapter 7 we’ll take an in-depth look at the containers in the Standard C++ library, including the stack container. One thing you’ll notice is that the declaration of the pop( ) member function looks like this:
void pop();
You might think it strange that pop( ) doesn’t return a value. Instead, it just removes the element at the top of the stack. To retrieve the top value, call top( ) before you call pop( ). There is an important reason for this behavior, and it has to do with
Suppose you are implementing a stack with a dynamic array (we’ll call it data and the counter integer count), and you try to write pop( ) so that it returns a value. The code for such a pop( ) might look something like this:
template
T stack
if (count == 0)
throw logic_error("stack underflow");
else
return data[--count];
}