Rust by Example

// Destructure `mutable_tuple` to change the value of `last`.

let (_, ref mut last) = mutable_tuple;

*last = 2u32;

}

println!("tuple is {:?}", mutable_tuple);

}

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Lifetimes

A lifetime is a construct the compiler (or more specifically, its borrow checker) uses to ensure all borrows are valid. Specifically, a variable's lifetime begins when it is created and ends when it is destroyed. While lifetimes and scopes are often referred to together, they are not the same.

Take, for example, the case where we borrow a variable via &. The borrow has a lifetime that is determined by where it is declared. As a result, the borrow is valid as long as it ends before the lender is destroyed. However, the scope of the borrow is determined by where the reference is used.

In the following example and in the rest of this section, we will see how lifetimes relate to scopes, as well as how the two differ.

// Lifetimes are annotated below with lines denoting the creation

// and destruction of each variable.

// `i` has the longest lifetime because its scope entirely encloses

// both `borrow1` and `borrow2`. The duration of `borrow1` compared

// to `borrow2` is irrelevant since they are disjoint.

fn main() {

let i = 3; // Lifetime for `i` starts. ────────────────┐

// │

{ // │

let borrow1 = &i // `borrow1` lifetime starts. ──┐│

// ││

println!("borrow1: {}", borrow1); // ││

} // `borrow1 ends. ──────────────────────────────────┘│

// │

// │

{ // │

let borrow2 = &i // `borrow2` lifetime starts. ──┐│

// ││

println!("borrow2: {}", borrow2); // ││

} // `borrow2` ends. ─────────────────────────────────┘│

// │

} // Lifetime ends. ─────────────────────────────────────┘

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